(8x+1)(2x^2+13x-7)=0

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Solution for (8x+1)(2x^2+13x-7)=0 equation: 


Simplifying
(8x + 1)(2x2 + 13x + -7) = 0

Reorder the terms:
(1 + 8x)(2x2 + 13x + -7) = 0

Reorder the terms:
(1 + 8x)(-7 + 13x + 2x2) = 0

Multiply (1 + 8x) * (-7 + 13x + 2x2)
(1(-7 + 13x + 2x2) + 8x * (-7 + 13x + 2x2)) = 0
((-7 * 1 + 13x * 1 + 2x2 * 1) + 8x * (-7 + 13x + 2x2)) = 0
((-7 + 13x + 2x2) + 8x * (-7 + 13x + 2x2)) = 0
(-7 + 13x + 2x2 + (-7 * 8x + 13x * 8x + 2x2 * 8x)) = 0
(-7 + 13x + 2x2 + (-56x + 104x2 + 16x3)) = 0

Reorder the terms:
(-7 + 13x + -56x + 2x2 + 104x2 + 16x3) = 0

Combine like terms: 13x + -56x = -43x
(-7 + -43x + 2x2 + 104x2 + 16x3) = 0

Combine like terms: 2x2 + 104x2 = 106x2
(-7 + -43x + 106x2 + 16x3) = 0

Solving
-7 + -43x + 106x2 + 16x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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